摘要: for file in ./* ; do mv "$file" "$(echo $file|sed -e 's/\([A-Z]\)/_\L\1/g' -e 's/^.\/_//')" ; done 批量修改文件名 for filename in *foo*; do echo mv \"$filena 阅读全文
posted @ 2020-12-17 10:07 wolbo 阅读(102) 评论(0) 推荐(0)