2025年7月30日
摘要: SELECT J.name AS JobName, CASE WHEN SJ.last_run_time = 0 THEN NULL ELSE STUFF(STUFF(RIGHT('000000' + CAST(SJ.last_run_time AS VARCHAR(6)), 6), 3, 0, ' 阅读全文
posted @ 2025-07-30 17:23 wakaka_wka 阅读(6) 评论(0) 推荐(0)