摘要:
# 方法一:def fib(n): if n <= 2: return 1 else: return fib(n-1) + fib(n-2) for i in range(1,10): print(f'fib({i}) = {fib(i)}') # 方法二: def fab(max): n, a, b = 0, 0, 1 while n < max: print(b) a, b = b, a + 阅读全文
posted @ 2019-10-04 15:33
wintalau
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