2021年2月2日
dotcpp-1095: 3n+1 problem
摘要： /* Consider the following algorithm to generate a sequence of numbers. Start with an integer n. If n is even, divide by 2. If n is odd, multiply by 3 阅读全文
posted @ 2021-02-02 21:39 jiangyz3 阅读(127) 评论(0) 推荐(0)
C语言递归输入输出数字
摘要： #include <stdio.h> #define N 6 void input(int *p,int n); void ouput(int *p,int n); int main(){ int a[N]; input(a,N); ouput(a,N); return 0; } void inpu 阅读全文
posted @ 2021-02-02 17:09 jiangyz3 阅读(430) 评论(0) 推荐(0)