随笔分类 - HDU
摘要:Problem DescriptionGive you a sequence of N(N≤100,000) integers : a1,...,an(0#include #include #include #include using namespace std;typedef long long...
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摘要:Problem DescriptionAn abandoned country has n(n≤100000) villages which are numbered from 1 to n. Since abandoned for a long time, the roads need to be...
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摘要:Palace Accepts: 28 Submissions: 307 Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)问题描述为了寻找失去的爱人Cupid,Psyche需要完成...
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摘要:Wool Accepts: 109 Submissions: 770 Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)问题描述黎明时,Venus为Psyche定下了第二个任务。她...
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摘要:Arrange Accepts: 221 Submissions: 1401 Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)问题描述Cupid一不小心将爱情之箭射到了自己,他爱...
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摘要:Oracle Accepts: 599 Submissions: 2576 Time Limit: 8000/4000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)问题描述曾经有一位国王,统治着一片未名之地。他膝下有三...
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摘要:题目大意:给你n个点,代表toy,求一个使得可以套住一个toy且只能套住一个toy的环的最大半径。解法:只需要求出所有点的最近点对的长度就可以解决了。但是如何求最近点对? 最容易想到的就是暴力枚举所有点对,求出最小长度,然后就可以得到结果。但是复杂度为O(n^2)而这题n的范围是10...
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摘要:这题是来自BestCoder Round #66的一道题目,不是很难,官方题解上说的也比较清楚了。O(nlog(n))的算法真心没考虑,一开始想的就是O(n)的算法,看了题解之后居然还是没想到O(nlogn)的算法怎么写。其实仔细想想,在第Ci秒结束时,B1, B2, B3, ... Bci都增加1...
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摘要:Problem DescriptionIgnatius has just come back school from the 30th ACM/ICPC. Now he has a lot of homework to do. Every teacher gives him a deadline o...
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摘要:Problem Description AFA is a girl who like runing.Today,he download an app about runing .The app can record the trace of her runing.AFA will s...
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摘要:Problem Description ZJiaQ want to become a strong man, so he decided to play the mook jong。ZJiaQ want to put some mook jongs in his backyard. ...
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摘要:Problem DescriptionTina Town is a friendly place. People there care about each other.Tina has a ball called zball. Zball is magic. It grows larger eve...
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