随笔分类 -  数学--基础

HDU 4112 Break the Chocolate(简单的数学推导)
摘要：Break the ChocolateTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4556Accepted Submission(s): 145... 阅读全文
posted @ 2015-08-26 00:21 BYYB_0506 阅读(286) 评论(0) 推荐(0)
求一个数的分解
摘要：1 # include 2 # include 3 # include 4 # include 5 6 using namespace std; 7 8 # define MAX 123 9 10 int prime[MAX];11 int ex[MAX];12 int cnt;13 14 1... 阅读全文
posted @ 2015-05-16 20:44 BYYB_0506 阅读(268) 评论(0) 推荐(0)
NWPU_四月月赛
摘要：MD，这场月赛知道的时候，只剩下不到一半的时间了，于是在比赛结束前，立马拿下3道签到题，还不算太渣。C - A+BTime Limit:5000ms Memory Limit:65536KBSubmitDescription有一个n个数的序列，每个数都是不同的，从这个序列中选出四个数问有多少个四元... 阅读全文
posted @ 2015-04-28 00:25 BYYB_0506 阅读(173) 评论(0) 推荐(0)
LightOJ 1109 - False Ordering (因式分解)
摘要：1109 - False OrderingPDF (English)StatisticsForumTime Limit:1 second(s)Memory Limit:32 MBWe definebis a Divisor of a numberaifais divisible byb. So, t... 阅读全文
posted @ 2015-04-27 13:23 BYYB_0506 阅读(374) 评论(0) 推荐(0)
UVA 294 Divisors( 因子分解)
摘要：294 DivisorsMathematicians love all sorts of odd properties of numbers. For instance, they consider 945 to be aninteresting number, since it is the r... 阅读全文
posted @ 2015-04-23 21:15 BYYB_0506 阅读(315) 评论(0) 推荐(0)
POJ 2739 Sum of Consecutive Prime Numbers(水题)
摘要：Sum of Consecutive Prime NumbersTime Limit:1000MSMemory Limit:65536KTotal Submissions:20560Accepted:11243DescriptionSome positive integers can be repr... 阅读全文
posted @ 2015-04-22 23:14 BYYB_0506 阅读(145) 评论(0) 推荐(0)
POJ 3132 Sum of Different Primes ( 满背包问题)
摘要：Sum of Different PrimesTime Limit:5000MSMemory Limit:65536KTotal Submissions:3280Accepted:2040DescriptionA positive integer may be expressed as a sum ... 阅读全文
posted @ 2015-04-22 00:59 BYYB_0506 阅读(216) 评论(0) 推荐(0)