2016/03/08 codes
摘要：
if(pointCount = 3){b2Distance.g_GJK_Iterations = iter;return 0.0;} var maxSqr = -Number.MAX_VALUE; for(var i = 0; i < pointCount; ++i){maxSqr = b2Math 阅读全文
posted @ 2016-03-08 11:47 琳姐姐 阅读(267) 评论(0) 推荐(0)
posted @ 2016-03-08 11:47 琳姐姐 阅读(267) 评论(0) 推荐(0)
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