1237. Find Positive Integer Solution for a Given Equation
Given a function f(x, y) and a value z, return all positive integer pairs x and y where f(x,y) == z.
The function is constantly increasing, i.e.:
f(x, y) < f(x + 1, y)f(x, y) < f(x, y + 1)
The function interface is defined like this:
interface CustomFunction {
public:
// Returns positive integer f(x, y) for any given positive integer x and y.
int f(int x, int y);
};
For custom testing purposes you're given an integer function_id and a target z as input, where function_id represent one function from an secret internal list, on the examples you'll know only two functions from the list.
You may return the solutions in any order.
Example 1:
Input: function_id = 1, z = 5 Output: [[1,4],[2,3],[3,2],[4,1]] Explanation: function_id = 1 means that f(x, y) = x + y
Example 2:
Input: function_id = 2, z = 5 Output: [[1,5],[5,1]] Explanation: function_id = 2 means that f(x, y) = x * y
Constraints:
1 <= function_id <= 91 <= z <= 100- It's guaranteed that the solutions of
f(x, y) == zwill be on the range1 <= x, y <= 1000 - It's also guaranteed that
f(x, y)will fit in 32 bit signed integer if1 <= x, y <= 1000
class Solution { public List<List<Integer>> findSolution(CustomFunction customfunction, int z) { List<List<Integer>> res = new ArrayList(); int x = 1, y = 1000; while(x <= 1000 && y > 0){ int v = customfunction.f(x, y); if (v > z) --y; else if (v < z) ++x; else res.add(Arrays.asList(x++, y--)); } return res; } }


浙公网安备 33010602011771号