518. Coin Change 2

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin.

Example 1:

Input: amount = 5, coins = [1, 2, 5]
Output: 4
Explanation: there are four ways to make up the amount:
5=5
5=2+2+1
5=2+1+1+1
5=1+1+1+1+1

Example 2:

Input: amount = 3, coins = [2]
Output: 0
Explanation: the amount of 3 cannot be made up just with coins of 2.

Example 3:

Input: amount = 10, coins = [10] 
Output: 1

Note:

You can assume that

0 <= amount <= 5000
1 <= coin <= 5000
the number of coins is less than 500
the answer is guaranteed to fit into signed 32-bit integer

class Solution {
  public int change(int amount, int[] coins) {
        int[] dp = new int[amount + 1];
        dp[0] = 1;        
        for (int j = 0; j < coins.length; j++) {
            for (int i = 1; i <= amount; i++) {
                if (i - coins[j] >= 0) {
                    dp[i] += dp[i - coins[j]];
                }
            }
        }
        return dp[amount];
    }
}