摘要: const int MAX_N = 1e3 + 50; int N, K; int mat[MAX_N][MAX_N]; void work(int len) { if (2 * len > MAX_N)//1024即可 return; for (int i = 1; i <= len; i++) 阅读全文
posted @ 2020-10-29 19:59 wansheking 阅读(82) 评论(0) 推荐(0)