实验一-熟悉C语言编程环境

#include<stdio.h>
int main(void)
{
    int digit,letter,other;
    char ch;
    int i;
    digit=letter=other=0;
    printf("Enter 10 characters:");
    for(i=1;i<=10;i++){
        ch=getchar();
        if((ch>='a'&&ch<='z')||(ch>'A'&&ch<='Z'))
            letter++;
        else if(ch>='0' && ch<='9')
            digit++;
        else
            other++;
    }
    printf("letter=%d,digit=%d,other=%d\n",letter,digit,other);

    return 0;

}

#include<stdio.h>
int main(void)
{
    int choice,i;
    double price;

    for(i=1;i<=5;i++){
       
        printf("[1]Select crisps \n");
        printf("[2]Select popcorn \n");
        printf("[3]Select chocolate \n");
        printf("[4]Select cola \n");
        printf("[0] exit \n");

        printf("Enter choice:");
        scanf("%d",&choice);

        
        if(choice==0)
            break;
        
        
        switch(choice){
            case 1:price=3.0;break;
            case 2:price=2.5;break;
            case 3:price=4.0;break;
            case 4:price=3.5;break;
            default:price=0.0;break;

        }
        
        printf("price=%0.1f\n",price);

    }
        printf("Thanks \n");

        return 0;

}

#include<stdio.h>
int main(void)
{
    double value1,value2;
    char op;

    printf("Type in an expression:");
    scanf("%if%c%if",&value1,&op,&value2);
    switch(op){
    case'+':
        printf("=%.2f\n",value1+value2);
        break;
    case'-':
        printf("=%.2f\n",value1-value2);
        break;
    case'*':
        printf("=%.2f\n",value1*value2);
        break;
    case'/':
        printf("=%.2f\n",value1/value2);
        break;
    default:
        printf("Unknown operator\n");
        break;

    }

    return 0;
}

#include<stdio.h>
int main(void)
{
    double value1,value2;
    char op;

    printf("Type in an expression:");
    scanf("%if%c%if",&value1,&op,&value2);
    if(op=='+')
        printf("=%.2f\n",value1+value2);
    else if(op=='-')
        printf("=%.2f\n",value1-value2);   
    else if(op=='*')
        printf("=%.2f\n",value1*value2);
    else if(op=='/')
        if(value2!=0)
            printf("=%.2f\n",value1/value2);
        else
            printf("Divisor can not be 0!\n");
    else
            printf("Unknown operator!\n");
    return 0;

}       

posted @ 2013-10-08 17:54  红颜文丛  阅读(187)  评论(0编辑  收藏  举报