08 2016 档案

string类里find的用法
摘要：#include<bits/stdc++.h> using namespace std; typedef long long ll; //int INF=(1<<31)-1; //int mi=-(1<<31)+1; #define read(x) scanf("%d",&x); #define f 阅读全文
posted @ 2016-08-22 01:07 俺叫王梦涵 阅读(508) 评论(0) 推荐(0)
java实现a+b的多重输入
摘要：import java.util.Scanner; public class hello { public static void main(String[] args) { Scanner cin = new Scanner(System.in); { while(cin.hasNextIn... 阅读全文
posted @ 2016-08-15 11:31 俺叫王梦涵 阅读(1325) 评论(0) 推荐(0)
二进制中1的个数
摘要：#include using namespace std; int main() { int n; cin>>n; cout<<__builtin_popcount(n)<<endl; } 阅读全文
posted @ 2016-08-14 00:32 俺叫王梦涵 阅读(141) 评论(0) 推荐(0)
codeforces#271 (Div. 2)预处理
摘要：B. Worms time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output It is lunch time for Mole. His f 阅读全文
posted @ 2016-08-13 23:00 俺叫王梦涵 阅读(171) 评论(0) 推荐(0)
Codeforces Round #279 (Div. 2) vector
摘要：A. Team Olympiad time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The School №0 of the cap 阅读全文
posted @ 2016-08-09 23:09 俺叫王梦涵 阅读(157) 评论(0) 推荐(0)
Codeforces Round B. Buttons
摘要：Manao is trying to open a rather challenging lock. The lock has n buttons on it and to open it, you should press the buttons in a certain order to ope 阅读全文
posted @ 2016-08-08 22:16 俺叫王梦涵 阅读(169) 评论(0) 推荐(0)
hdu4135 容斥定理
摘要：Co-prime Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3587 Accepted Submission(s): 1419 Proble 阅读全文
posted @ 2016-08-02 22:36 俺叫王梦涵 阅读(190) 评论(0) 推荐(1)