cli创建lambda函数并发布别名

import boto3

def lambda_handler(event,context):
s3 = boto3.resource('s3')
s3.create_bucket(Bucket='mys3bucket-123456')
content = 'v2'
s3.Object('mys3bucket-123456','v2.txt').put(Body=content)
print('is ok')

posted @ 2023-02-19 20:03  网络混混123  阅读(17)  评论(0)    收藏  举报