02 2017 档案
摘要:报错情况:在导入数据时候发现找不到InnoDB这个错误,之前查看博客时候明白了IsAsm数据库和InnoDB这两个的区别了。 解决方案: 尝试一:将my.ini配置文件的isasm改成InnoDB。这个是之前参考博客完成。但是这个没有奏效。 尝试二:想到这个应该是没有完成服务器的重启,但是通过php
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摘要:class Solution { public: vector<int> searchRange(vector<int>& nums, int target) { int idx = search(nums, 0, nums.size() - 1, target); if (idx == -1) r
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摘要:public class Solution { public int search(int[] A, int target) { int l = 0; int r = A.length - 1; while (l <= r) { int mid = (l + r) / 2; if (target =
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摘要:class Solution { public: int longestValidParentheses(string s) { int res = 0, start = 0; stack<int> m; for (int i = 0; i < s.size(); ++i) { if (s[i] =
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摘要:class Solution { public: void nextPermutation(vector<int> &num) { int i, j, n = num.size(); for (i = n - 2; i >= 0; --i) { if (num[i + 1] > num[i]) {
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摘要:class Solution { public: vector<int> findSubstring(string s, vector<string>& words) { if (s.empty() || words.empty()) return {}; vector<int> res; int
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摘要:class Solution { public: int divide(int dividend, int divisor) { long long res = 0; long long m = abs((long long)dividend), n = abs((long long)divisor
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摘要:class Solution { public: int strStr(string haystack, string needle) { if (needle.empty()) return 0; int m = haystack.size(), n = needle.size(); if (m
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摘要:class Solution { public: int removeElement(vector<int>& nums, int val) { int res = 0; for (int i = 0; i < nums.size(); ++i) { if (nums[i] != val) nums
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摘要:class Solution { public: int removeDuplicates(int A[], int n) { if (n <= 1) return n; int pre = 0, cur = 0; while (cur < n) { if (A[cur] == A[pre]) ++
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摘要:class Solution { public: ListNode* reverseKGroup(ListNode* head, int k) { ListNode *cur = head; for (int i = 0; i < k; ++i) { if (!cur) return head; c
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摘要:class Solution { public: ListNode* swapPairs(ListNode* head) { if (!head || !head->next) return head; ListNode *t = head->next; head->next = swapPairs
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摘要:struct cmp { bool operator () (ListNode *a, ListNode *b) { return a->val > b->val; } }; class Solution { public: ListNode *mergeKLists(vector<ListNode
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摘要:class Solution { public: vector<string> generateParenthesis(int n) { set<string> t; if (n == 0) t.insert(""); else { vector<string> pre = generatePare
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摘要:class Solution { public: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1) return l2; if (!l2) return l1; if (l1->val < l2->val) { l1->ne
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摘要:class Solution { public: bool isValid(string s) { stack<char> parentheses; for (int i = 0; i < s.size(); ++i) { if (s[i] == '(' || s[i] == '[' || s[i]
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摘要:class Solution { public: ListNode* removeNthFromEnd(ListNode* head, int n) { if (!head->next) return NULL; ListNode *pre = head, *cur = head; for (int
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摘要:class Solution { public: vector<vector<int> > fourSum(vector<int> &nums, int target) { set<vector<int> > res; sort(nums.begin(), nums.end()); for (int
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摘要:class Solution { public: vector<string> letterCombinations(string digits) { vector<string> res; if (digits.empty()) return res; string dict[] = {"abc"
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摘要:class Solution { public: int threeSumClosest(vector<int>& nums, int target) { int closest = nums[0] + nums[1] + nums[2]; int diff = abs(closest - targ
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摘要:class Solution { public: vector<vector<int>> threeSum(vector<int>& nums) { set<vector<int>> res; sort(nums.begin(), nums.end()); for (int k = 0; k < n
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摘要:class Solution { public: string longestCommonPrefix(vector<string>& strs) { if (strs.empty()) return ""; for (int j = 0; j < strs[0].size(); ++j) { fo
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摘要:class Solution { public: int romanToInt(string s) { int res = 0; unordered_map<char, int> m{{'I', 1}, {'V', 5}, {'X', 10}, {'L', 50}, {'C', 100}, {'D'
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摘要:class Solution { public: string intToRoman(int num) { string res = ""; vector<int> val{1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1}; vector<s
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摘要:class Solution { public: bool isMatch(string s, string p) { int m = s.size(), n = p.size(); vector<vector<bool>> dp(m + 1, vector<bool>(n + 1, false))
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摘要:class Solution {public: bool isPalindrome(int x) { //negative number if(x < 0) return false; int len = 1; while(x / len >= 10) len *= 10; while(x > 0)
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摘要:public class Solution { public int myAtoi(String str) { if (str.isEmpty()) return 0; int sign = 1, base = 0, i = 0, n = str.length(); while (i < n &&
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