摘要: int main() { //递归函数 int age(int n); printf("%d\n", age(5)); return 0; } int age(int n) { int c; if (n == 1) c = 10; else { c = age(n - 1) + 2; } retur 阅读全文
posted @ 2021-11-03 17:08 江南王小帅 阅读(16) 评论(0) 推荐(0)
摘要: //擂台法 int max, clu=0, row=0; int a[3][2] = { {1,15},{903,3},{48,95} }; int i ,j; max = a[0][0]; for ( i = 0; i < 3; i++) for ( j = 0; j < 2; j++) if ( 阅读全文
posted @ 2021-11-03 13:33 江南王小帅 阅读(132) 评论(0) 推荐(0)
摘要: int a[2][3]; int b[3][2]; for (int i = 0; i < 2; i++) { for (int j = 0; j < 3; j++) { scanf("%d", &a[i][j]); } } printf("arry a[2][3]:\n"); for (int i 阅读全文
posted @ 2021-11-03 11:46 江南王小帅 阅读(118) 评论(0) 推荐(0)
摘要: int a[10]; //冒泡法 printf("请输入10个数\n"); for (int i = 0; i < 10; i++) { scanf("%d", &a[i]); } for (int j = 0; j < 9; j++) //有N个数,则进行N-1次比较 { for (int i = 阅读全文
posted @ 2021-11-03 11:45 江南王小帅 阅读(629) 评论(0) 推荐(0)