实验二

任务一

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 5
#define R1 586
#define R2 701

int main ()
{
    int number;
    int i;
    
    srand(time(0));
    for(i=0;i<N;++i){
        number=rand()%(R2-R1+1)+R1;
        printf("20228330%04d\n",number);
    }
    return 0;
}

line18：生成一个R1到R2之间的随机整数

生成五个末尾从0586到0701的随机学号

 

任务二

#include <stdio.h>

int main ()
{
    double x,y;
    char c1,c2,c3;
    int a1,a2,a3;
    
    scanf ("%d%d%d",&a1,&a2,&a3);
    printf ("a1=%d,a2=%d,a3=%d\n",a1,a2,a3);
    
    scanf ("%c%c%c",&c1,&c2,&c3);
    printf ("c1=%c,c2=%c,c3=%c\n",c1,c2,c3);
    
    scanf ("%lf,%lf",&x,&y);
    printf ("x=%lf,y=%lf\n",x,y);
    
    return 0;
}

 

任务三

#include <stdio.h>
#include <math.h>

int main ()
{
    double x,ans;
    
    while (scanf("%lf",&x)!=EOF)
    {
        ans=pow(x,365);
        printf("%.2f的365次方为：%.2f\n",x,ans);
    }

    return 0;
}

 

#include <stdio.h>
#include <math.h>

int main ()
{
    double C,F;
    
    while (scanf("%lf",&C)!=EOF)
    {
        F=C*9/5+32;
        printf ("摄氏度为%.2f时，华氏度为%.2f\n",C,F);
        
    }

    return 0;
}

 

 

任务四

#include <stdio.h>

int main ()
{
    char Y;
    
    while (scanf("%c",&Y)!=EOF)
    {
        switch (Y)
        {
        case 'y':printf ("wait\n");
        break;
        case 'g':printf ("go\n");
        break;
        case 'r':printf ("stop\n");
        break;
        default:printf ("wrong\n");
        break;
        }
        getchar();
    }

    return 0;
}

 

任务五

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main ()
{
    printf ("guess which day in 4,2023 will be your lucky day\n");
    
    printf ("let's start the game. you have three chances to try(1~30):\n");
    
    int day,i,a;
    
    srand(time(0));
    
    day=rand()%30+1;
    
    i=3;
    
    while (i>0)
    {
        
        i--;
        
        scanf ("%d",&a);
        
        if(a>day)
        {
            printf ("too late\n");
        }
        
        if(a==day)
        {
            printf ("bingo\n");
            break;
        }
        
        if(a<day)
        {
            printf ("too early\n");
        }
    }
    
    printf ("your lucky day:%d",day);
    
    return 0;
}

 

任务六

#include <stdio.h>
#include <stdlib.h>
 
int main ()
{
    int x,y,a;
    
    for (y=1;y<10;y++)
    {
        for (x=1;x<=y;x++)
        {
            a=x*y;
            
            printf ("%d*%d=%d\t",x,y,a);
        }
        printf ("\n");
    }
    
    return 0;
}

 

任务七

#include <stdio.h>
#include <stdlib.h>
 
int main ()
{
    int x,y,n;
    
    scanf ("%d",&y);
    for(n=1;n<=y;n++)
    {
        for(x=1;x<=n-1;x++)
        {
            printf("\t");
        }

        for(x=1;x<=(y-n)*2+1;x++)
        
        {
            printf(" O \t");
        }
        
        printf("\n");

        for(x=1;x<=n-1;x++)
        
        {
            printf("\t");
        }
        
        for(x=1;x<=(y-n)*2+1;x++)
        
        {
            printf("<H>\t");
        }
        
        printf("\n");
        
        for(x=1;x<=n-1;x++)
        
        {
            printf("\t");
        }
        
        for(x=1;x<=(y-n)*2+1;x++)
        
        {
            printf("I I\t");
        }
        
        printf("\n");
        
    }
    
    
    return 0;
}

第n行，打印2（y-n）+1个小人，需要2n-2个\t