poj 2641 Billiard
Billiard
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 1160 | Accepted: 736 |
Description
In a billiard table with horizontal side a inches and vertical side b inches, a ball is launched from the middle of the table. After s > 0 seconds the ball returns to the point from which it was launched, after having made m bounces off the vertical sides and n bounces off the horizontal sides of the table. Find the launching angle A (measured from the horizontal), which will be between 0 and 90 degrees inclusive, and the initial velocity of the ball.
Assume that the collisions with a side are elastic (no energy loss), and thus the velocity component of the ball parallel to each side remains unchanged. Also, assume the ball has a radius of zero. Remember that, unlike pool tables, billiard tables have no pockets.
Assume that the collisions with a side are elastic (no energy loss), and thus the velocity component of the ball parallel to each side remains unchanged. Also, assume the ball has a radius of zero. Remember that, unlike pool tables, billiard tables have no pockets.
Input
Input consists of a sequence of lines, each containing five nonnegative integers separated by whitespace. The five numbers are: a, b, s, m, and n, respectively. All numbers are positive integers not greater than 10000.
Input is terminated by a line containing five zeroes.
Input is terminated by a line containing five zeroes.
Output
For each input line except the last, output a line containing two real numbers (accurate to two decimal places) separated by a single space. The first number is the measure of the angle A in degrees and the second is the velocity of the ball measured in inches per second, according to the description above.
Sample Input
100 100 1 1 1 200 100 5 3 4 201 132 48 1900 156 0 0 0 0 0
Sample Output
45.00 141.42 33.69 144.22 3.09 7967.81
#include<iostream>
#include<iomanip>
#include<cmath>
using namespace std;
const double Pi=3.141592653;
int main()
{
double a,b,s,m,n;
while(cin>>a>>b>>s>>m>>n)
{
double degree1,degree2,v;
if(a==0&&b==b&&s==0&&m==0&&n==0)
break;
degree1=atan(n*b/(m*a));
v=(b*n)/(sin(degree1)*s);
degree2=degree1/Pi*180.0;
cout<<fixed<<setprecision(2)<<degree2<<''<<v<<endl;
}
return 0;
}
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