如何验证15位身份证号码
请问如何验证15位身份证号码？－在线等待
在线等待
大家帮帮忙?gt;>?br>
ValidationExpression="^\d{15}$"
最好能给我完整的代码，我不需要政则表达式。谢谢。
楼上说得正确
ValidationExpression="^\d{15}$"
<asp:RegularExpressionValidator id="RegularExpressionValidator1" runat="server"
ControlToValidate="TextBox1"
ValidationExpression="^\d{15}$"
Display="Static"
Font-Name="verdana"
Font-Size="10pt">
请输入正确的身份号码！
</asp:RegularExpressionValidator>
我不要这个脚本的语言，我要的是一个function的函数，验证通过，返回true，验证错误，返回flase。
你想怎么验证?gt;>９Ｄ阌置挥泄不氐纳矸葜た猓阕疃嘌橹こざ榷圆欢裕蚴前焉矸葜さ哪暝氯仗岢隼矗胗没ё砸烟畹哪暝氯展ぷ识员龋词欠裣嗤渌鼓苎橹な裁矗?br>
郁闷，得不到我想要得答案，如何结贴？
以前写的，根据你的具体环境做一些调整吧
//校验出生日期和18位的校验和
//局限：日期校验的时候是1900－1999，可以根据具体的需要调整
//Test Passed in IE6.0
//By pxk, pxknet@163.com
//检查身份证号，支持15和18位。返回值表示错误原因。""表示无错
function CheckIDCard(strID)
{
//验证各位字符是否合法的正则表达式
ReDigital15 = /\d{15}/;
ReDigital18 = /\d{17}[0-9xX]{1}/;
//提取日期和校验的正则表达式
ReDate15 = /\d{6}(\d{6})\d{3}/;
ReDate18 = /\d{6}(\d{8})\d{3}/;
switch(strID.length)
{
case 15:
if( ReDigital15.test( strID ) == false )
return "非法字符";
Arr = ReDate15.exec( strID );
strDate = "19" + Arr[1];
if( CheckDate(strDate, new Date(1900,0,1), new Date(1999,11,31)) == false )
return "日期无效";
break;
case 18:
if( ReDigital18.test( strID ) == false )
return "非法字符";
Arr = ReDate18.exec( strID );
strDate = Arr[1];
if( CheckDate(strDate, new Date(1900,0,1), new Date()) == false )
return "日期无效";
if( CheckSum( strID ) == false )
return "校验错误";
break;
default:
return "位数不对";
break;
}
return "";
}
//对身份证的校验位进行验证
function CheckSum( strID )
{
//debugger;
//18位数字提取正则表达式
Re18Digital = /(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})([0-9xX]{1})/;
Arr = Re18Digital.exec(strID);
var Wi = new Array(7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2);
Sum = 0;
for(i=0;i<=16;i++)
Sum += Arr[i+1] * Wi[i];
ArrCheckSum = new Array('1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2');
strCheckSum = ArrCheckSum[Sum%11];
if( strCheckSum == Arr[18].toUpperCase() )
return true;
else
return false;
}
//检查在指定范围之内的日期，支持选择框自动生成格式和手动连打格式。返回bool，true表示日期有效，false表示日期无效。
function CheckDate( strDate, DateFrom, DateTo )
{
//手动日期验证正则表达式
ReDigital8 = /\d{8}/;
//自动日期验证正则表达式
ReAutoDate = /\d{4}-{1}\d{1,2}-\d{1,2}/;
//自动日期提取正则表达式
//ReGetDate = /(\d{4})-{1}(\d{1,2})-(\d{1,2})/;
//debugger;
if(strDate.indexOf("-")>-1)
{
if( ReAutoDate.test( strDate ) == false )
return false;
//Arr = ReGetDate.exec( strDate );
Arr = strDate.split("-");
strDate = (Arr[0]) + "" + (Arr[1].length<2?"0":"") + Arr[1] + (Arr[2].length<2?"0":"") + (Arr[2]);
}
if(strDate.length!=8)
return false;
if( ReDigital8.test(strDate)==false )
return false;
MyDate = eval( strDate.replace( /^(\d{4})(\d{2})(\d{2})$/, "new Date($1,$2-1,$3)" ) );
strMyDate = MyDate.getFullYear()+(MyDate.getMonth()<9?"0":"")+(MyDate.getMonth()+1)+""+(MyDate.getDate()<=9?"0":"")+MyDate.getDate();
//日期有效性验证
if(strMyDate!=strDate)
return false;
//日期范围验证
if( MyDate>=DateFrom && MyDate<=DateTo )
return true;
else
return false;
}
ValidationExpression="^\d{15}$"
对啊，你如果不能连到公安机关数据库去查询的话，这样做无意义
楼上说的对,确实!
Public Function getCheckCode(ByVal SFZH As String) As String
Dim strJiaoYan() As Char = {"1", "0", "X", "9", "8", "7", "6", "5", "4", "3", "2"}
Dim intQuan() As Integer = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2, 1}
Dim strTemp As String
Dim intTemp As String
Dim i As Integer
strTemp = SFZH.Substring(0, 6) & "19" & SFZH.Substring(6)
For i = 0 To strTemp.Length - 1
intTemp = intTemp + Convert.ToInt32(strTemp.Substring(i, 1)) * intQuan(i)
Next
intTemp = intTemp Mod 11
Return strTemp & strJiaoYan(intTemp)
End Function
http://community.csdn.net/Expert/topic/3891/3891579.xml?temp=.5628015
如果用的是VS的话
就在aspx页子里拉除一个ValidationExpression验证控件
然后在属性里定义^\d{15}$
身份证号并不都是十五位，应搞个取值范围吧>>如15－18
有个算法的。
15位身份证验证:
位数:15位
内容全部为数值
7-12位 为出生日期
就这么几项,写个函数很简单呀
如果不能连到公安机关数据库去查询的话,就只有判断一下是不是15位数字,其他的都没有意思.用正则表达式就可以了
就像楼上说的,要么15就18位,不能限死330的,下面是正则表达式(我不喜欢自带的验证控件,从Label继承的,占地方!)
public string IsID(string Inputvalue)
{ /* 判断输入是否为身份证*/
if(Inputvalue=="")return "";
string pattern = @"([0-9]{14}[x0-9]{1})|([0-9]{17}[x0-9]{1})";
Match m = Regex.Match(Inputvalue,pattern);
if(m.Success)
{
return "";
}
else
{
return "身份证格式不正确";
}
}
\d{18}|\d{15}
18位的话，最后一位有可能是 字母
VS里的RegularExpressionValidator控件，设置ValidationExpression为中国身份证验证
但是这样的验证不是很精确只是接受15位或18位的数字，更确切的验证要在服务器端进行身份证规则判断
再Up
我也要这样的验证方法啊,一直无犁头
这是我目前使用的验证17位身份证号码的函数：
Public Shared Function CheckCidInfo(ByVal cid As String) As Boolean
Dim aCity() As String = {"", "", "", "", "", "", "", "", "", "", _
"", "北京", "天津", "河北", "山西", "内蒙古", "", _
"", "", "", "", "辽宁", "吉林", "黑龙江", "", "", _
"", "", "", "", "", "上海", "江苏", "浙江", "安微", _
"福建", "江西", "山东", "", "", "", "河南", "湖北", _
"湖南", "广东", "广西", "海南", "", "", "", "重庆", _
"四川", "贵州", "云南", "西藏", "", "", "", "", "", _
"", "陕西", "甘肃", "青海", "宁夏", "新疆", "", "", _
"", "", "", "台湾", "", "", "", "", "", "", "", "", _
"", "香港", "澳门", "", "", "", "", "", "", "", "", "国外"}
Dim iSum As Double = 0
Dim info As String = ""
Dim rg As System.Text.RegularExpressions.Regex = New System.Text.RegularExpressions.Regex("^\d{17}(\d|x)$")
Dim mc As System.Text.RegularExpressions.Match = rg.Match(cid)
If mc.Success = False Then
Return False
End If
cid = cid.ToLower
cid = cid.Replace("x", "a")
If aCity(Integer.Parse(cid.Substring(0, 2))) = "" Then
'Return "非法地址"
Return False
End If
Try
DateTime.Parse(cid.Substring(6, 4) & "-" & cid.Substring(10, 2) & "-" & cid.Substring(12, 2))
Catch ex As Exception
'Return "非法生日"
Return False
End Try
Dim i As Integer
For i = 17 To 0 Step -1
iSum = iSum + (System.Math.Pow(2, i) Mod 11) * Integer.Parse(cid.Substring(17 - i, 1), System.Globalization.NumberStyles.HexNumber)
'
Next
If iSum Mod 11 <> 1 Then
'Return "非法证号"
Return False
End If
Dim strSex As String
If (Integer.Parse(cid.Substring(16, 1)) Mod 2) = 1 Then
strSex = "男"
Else
strSex = "女"
End If
'Return aCity(Integer.Parse(cid.Substring(0, 2))) & "," & cid.Substring(6, 4) & "-" & cid.Substring(10, 2) & "-" & cid.Substring(12, 2) & "," & strSex
Return True
End Function
本人只想要一个和这个差不多的验证函数。
如果不能连到公安机关数据库去查询的话,就只有判断一下是不是15或18位数字,其他的根据特定的要求.用正则表达式就可以了
好的，结贴。
在线等待
大家帮帮忙?gt;>?br>
ValidationExpression="^\d{15}$"
最好能给我完整的代码，我不需要政则表达式。谢谢。
楼上说得正确
ValidationExpression="^\d{15}$"
<asp:RegularExpressionValidator id="RegularExpressionValidator1" runat="server"
ControlToValidate="TextBox1"
ValidationExpression="^\d{15}$"
Display="Static"
Font-Name="verdana"
Font-Size="10pt">
请输入正确的身份号码！
</asp:RegularExpressionValidator>
我不要这个脚本的语言，我要的是一个function的函数，验证通过，返回true，验证错误，返回flase。
你想怎么验证?gt;>９Ｄ阌置挥泄不氐纳矸葜た猓阕疃嘌橹こざ榷圆欢裕蚴前焉矸葜さ哪暝氯仗岢隼矗胗没ё砸烟畹哪暝氯展ぷ识员龋词欠裣嗤渌鼓苎橹な裁矗?br>
郁闷，得不到我想要得答案，如何结贴？
以前写的，根据你的具体环境做一些调整吧
//校验出生日期和18位的校验和
//局限：日期校验的时候是1900－1999，可以根据具体的需要调整
//Test Passed in IE6.0
//By pxk, pxknet@163.com
//检查身份证号，支持15和18位。返回值表示错误原因。""表示无错
function CheckIDCard(strID)
{
//验证各位字符是否合法的正则表达式
ReDigital15 = /\d{15}/;
ReDigital18 = /\d{17}[0-9xX]{1}/;
//提取日期和校验的正则表达式
ReDate15 = /\d{6}(\d{6})\d{3}/;
ReDate18 = /\d{6}(\d{8})\d{3}/;
switch(strID.length)
{
case 15:
if( ReDigital15.test( strID ) == false )
return "非法字符";
Arr = ReDate15.exec( strID );
strDate = "19" + Arr[1];
if( CheckDate(strDate, new Date(1900,0,1), new Date(1999,11,31)) == false )
return "日期无效";
break;
case 18:
if( ReDigital18.test( strID ) == false )
return "非法字符";
Arr = ReDate18.exec( strID );
strDate = Arr[1];
if( CheckDate(strDate, new Date(1900,0,1), new Date()) == false )
return "日期无效";
if( CheckSum( strID ) == false )
return "校验错误";
break;
default:
return "位数不对";
break;
}
return "";
}
//对身份证的校验位进行验证
function CheckSum( strID )
{
//debugger;
//18位数字提取正则表达式
Re18Digital = /(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})(\d{1})([0-9xX]{1})/;
Arr = Re18Digital.exec(strID);
var Wi = new Array(7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2);
Sum = 0;
for(i=0;i<=16;i++)
Sum += Arr[i+1] * Wi[i];
ArrCheckSum = new Array('1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2');
strCheckSum = ArrCheckSum[Sum%11];
if( strCheckSum == Arr[18].toUpperCase() )
return true;
else
return false;
}
//检查在指定范围之内的日期，支持选择框自动生成格式和手动连打格式。返回bool，true表示日期有效，false表示日期无效。
function CheckDate( strDate, DateFrom, DateTo )
{
//手动日期验证正则表达式
ReDigital8 = /\d{8}/;
//自动日期验证正则表达式
ReAutoDate = /\d{4}-{1}\d{1,2}-\d{1,2}/;
//自动日期提取正则表达式
//ReGetDate = /(\d{4})-{1}(\d{1,2})-(\d{1,2})/;
//debugger;
if(strDate.indexOf("-")>-1)
{
if( ReAutoDate.test( strDate ) == false )
return false;
//Arr = ReGetDate.exec( strDate );
Arr = strDate.split("-");
strDate = (Arr[0]) + "" + (Arr[1].length<2?"0":"") + Arr[1] + (Arr[2].length<2?"0":"") + (Arr[2]);
}
if(strDate.length!=8)
return false;
if( ReDigital8.test(strDate)==false )
return false;
MyDate = eval( strDate.replace( /^(\d{4})(\d{2})(\d{2})$/, "new Date($1,$2-1,$3)" ) );
strMyDate = MyDate.getFullYear()+(MyDate.getMonth()<9?"0":"")+(MyDate.getMonth()+1)+""+(MyDate.getDate()<=9?"0":"")+MyDate.getDate();
//日期有效性验证
if(strMyDate!=strDate)
return false;
//日期范围验证
if( MyDate>=DateFrom && MyDate<=DateTo )
return true;
else
return false;
}
ValidationExpression="^\d{15}$"
对啊，你如果不能连到公安机关数据库去查询的话，这样做无意义
楼上说的对,确实!
Public Function getCheckCode(ByVal SFZH As String) As String
Dim strJiaoYan() As Char = {"1", "0", "X", "9", "8", "7", "6", "5", "4", "3", "2"}
Dim intQuan() As Integer = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2, 1}
Dim strTemp As String
Dim intTemp As String
Dim i As Integer
strTemp = SFZH.Substring(0, 6) & "19" & SFZH.Substring(6)
For i = 0 To strTemp.Length - 1
intTemp = intTemp + Convert.ToInt32(strTemp.Substring(i, 1)) * intQuan(i)
Next
intTemp = intTemp Mod 11
Return strTemp & strJiaoYan(intTemp)
End Function
http://community.csdn.net/Expert/topic/3891/3891579.xml?temp=.5628015
如果用的是VS的话
就在aspx页子里拉除一个ValidationExpression验证控件
然后在属性里定义^\d{15}$
身份证号并不都是十五位，应搞个取值范围吧>>如15－18
有个算法的。
15位身份证验证:
位数:15位
内容全部为数值
7-12位 为出生日期
就这么几项,写个函数很简单呀
如果不能连到公安机关数据库去查询的话,就只有判断一下是不是15位数字,其他的都没有意思.用正则表达式就可以了
就像楼上说的,要么15就18位,不能限死330的,下面是正则表达式(我不喜欢自带的验证控件,从Label继承的,占地方!)
public string IsID(string Inputvalue)
{ /* 判断输入是否为身份证*/
if(Inputvalue=="")return "";
string pattern = @"([0-9]{14}[x0-9]{1})|([0-9]{17}[x0-9]{1})";
Match m = Regex.Match(Inputvalue,pattern);
if(m.Success)
{
return "";
}
else
{
return "身份证格式不正确";
}
}
\d{18}|\d{15}
18位的话，最后一位有可能是 字母
VS里的RegularExpressionValidator控件，设置ValidationExpression为中国身份证验证
但是这样的验证不是很精确只是接受15位或18位的数字，更确切的验证要在服务器端进行身份证规则判断
再Up
我也要这样的验证方法啊,一直无犁头
这是我目前使用的验证17位身份证号码的函数：
Public Shared Function CheckCidInfo(ByVal cid As String) As Boolean
Dim aCity() As String = {"", "", "", "", "", "", "", "", "", "", _
"", "北京", "天津", "河北", "山西", "内蒙古", "", _
"", "", "", "", "辽宁", "吉林", "黑龙江", "", "", _
"", "", "", "", "", "上海", "江苏", "浙江", "安微", _
"福建", "江西", "山东", "", "", "", "河南", "湖北", _
"湖南", "广东", "广西", "海南", "", "", "", "重庆", _
"四川", "贵州", "云南", "西藏", "", "", "", "", "", _
"", "陕西", "甘肃", "青海", "宁夏", "新疆", "", "", _
"", "", "", "台湾", "", "", "", "", "", "", "", "", _
"", "香港", "澳门", "", "", "", "", "", "", "", "", "国外"}
Dim iSum As Double = 0
Dim info As String = ""
Dim rg As System.Text.RegularExpressions.Regex = New System.Text.RegularExpressions.Regex("^\d{17}(\d|x)$")
Dim mc As System.Text.RegularExpressions.Match = rg.Match(cid)
If mc.Success = False Then
Return False
End If
cid = cid.ToLower
cid = cid.Replace("x", "a")
If aCity(Integer.Parse(cid.Substring(0, 2))) = "" Then
'Return "非法地址"
Return False
End If
Try
DateTime.Parse(cid.Substring(6, 4) & "-" & cid.Substring(10, 2) & "-" & cid.Substring(12, 2))
Catch ex As Exception
'Return "非法生日"
Return False
End Try
Dim i As Integer
For i = 17 To 0 Step -1
iSum = iSum + (System.Math.Pow(2, i) Mod 11) * Integer.Parse(cid.Substring(17 - i, 1), System.Globalization.NumberStyles.HexNumber)
'
Next
If iSum Mod 11 <> 1 Then
'Return "非法证号"
Return False
End If
Dim strSex As String
If (Integer.Parse(cid.Substring(16, 1)) Mod 2) = 1 Then
strSex = "男"
Else
strSex = "女"
End If
'Return aCity(Integer.Parse(cid.Substring(0, 2))) & "," & cid.Substring(6, 4) & "-" & cid.Substring(10, 2) & "-" & cid.Substring(12, 2) & "," & strSex
Return True
End Function
本人只想要一个和这个差不多的验证函数。
如果不能连到公安机关数据库去查询的话,就只有判断一下是不是15或18位数字,其他的根据特定的要求.用正则表达式就可以了
好的，结贴。
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