AcWing 1470. 水桶传递队列
题目链接
题目思路
没有技巧,全是感情,bfs经典模板题
题目代码
#include <iostream>
#include <algorithm>
#include <cstring>
#include <queue>
using namespace std;
typedef pair<int, int> PII;
const int N = 20;
char g[N][N];
int dist[N][N];
bool st[N][N];
int bfs(int x, int y)
{
memset(dist, -1, sizeof dist);
queue<PII> q;
q.push({x, y});
dist[x][y] = 0;
st[x][y] = true;
while(q.size())
{
auto t = q.front();
q.pop();
int dx[x] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
for(int i = 0; i < 4; i ++ )
{
int a = t.first + dx[i], b = t.second + dy[i];
if(a >= 0 && a < 10 && b >= 0 && b < 10 && !st[a][b] && g[a][b] != 'R')
{
dist[a][b] = dist[t.first][t.second] + 1;
st[a][b] = true;
q.push({a, b});
if(g[a][b] == 'L') return dist[a][b] - 1;
}
}
}
}
int main()
{
int x, y;
for(int i = 0; i < 10; i ++ )
{
for(int j = 0; j < 10; j ++ )
{
cin >> g[i][j];
if(g[i][j] == 'B')
{
x = i, y = j;
}
}
}
cout << bfs(x, y) << endl;
return 0;
}
孤独本是常态

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