摘要:
#define N 10int lis[N+1][N+1];int *LIS(int *a){ for (int i=1; i<=N; i++) { lis[i][0]=1; lis[i][1]=a[i]; for (int j=1;j<i; j++) { if (a[i]>lis[j][lis[j][0]]) { lis[j][0]++; lis[j][lis[j][0]] = a[i]; } ... 阅读全文
posted @ 2012-05-15 23:04
windflying
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