摘要:
void inv(mat &x){ int n = 2, is[2], js[2]; memset(is, 0, sizeof(is)); memset(js, 0, sizeof(js)); for (int k = 0; k < n; k++) { for (int i = k, j; i < 阅读全文
摘要:
http://ica.openjudge.cn/function1/3/ const int N =1004; int n,m,f[N][N]; char a[N],b[N]; signed main(){ int i,j; cin>>a+1>>b+1; n=strlen(a+1); m=strle 阅读全文