实验3

实验任务1

源代码:

button.hpp:

#pragma once

#include <iostream>
#include <string>

class Button {
public:
    Button(const std::string &label_);
    const std::string& get_label() const;
    void click();

private:
    std::string label;
};

Button::Button(const std::string &label_): label{label_} {
}

inline const std::string& Button::get_label() const {
    return label;
}

inline void Button::click() {
    std::cout << "Button '" << label << "' clicked\n";
}

 

window.hpp:

#pragma once

#include <iostream>
#include <vector>
#include <algorithm>
#include "button.hpp"

class Window{
public:
    Window(const std::string &title_);
    void display() const;
    void close();
    void add_button(const std::string &label);
    void click_button(const std::string &label);

private:
    bool has_button(const std::string &label) const;

private:
    std::string title;
    std::vector<Button> buttons;
};

Window::Window(const std::string &title_): title{title_} {
    buttons.push_back(Button("close"));
}

inline void Window::display() const {
    std::string s(40, '*');
    std::cout << s << std::endl;
    std::cout << "window : " << title << std::endl;
    int cnt = 0;
    for(const auto &button: buttons)
        std::cout << ++cnt << ". " << button.get_label() << std::endl;
    std::cout << s << std::endl;
}

inline void Window::close() {
    std::cout << "close window '" << title << "'" << std::endl;
    click_button("close");
}

inline bool Window::has_button(const std::string &label) const {
    for(const auto &button: buttons)
        if(button.get_label() == label)
            return true;
    
    return false;
}

inline void Window::add_button(const std::string &label) {
    if(has_button(label))
        std::cout << "button " << label << " already exists!\n";
    else
        buttons.push_back(Button(label));
}

inline void Window::click_button(const std::string &label) {
    for(auto &button:buttons)
        if(button.get_label() == label) {
            button.click();
            return;
        }
            
    std::cout << "no button: " << label << std::endl;
}

 

task1.cpp:

#include "window.hpp"
#include <iostream>

void test(){
    Window w("Demo");
    w.add_button("add");
    w.add_button("remove");
    w.add_button("modify");
    w.add_button("add");
    w.display();
    w.close();
}

int main() {
    std::cout << "用组合类模拟简单GUI:\n";
    test();
}

 

运行结果截图:

任务1

问题1:

window和Button是组合关系,window中有vector<Button>

问题2:

(1)优点:这个函数可以被外部调用;风险:破坏了类的封装性,会导致内部消息泄露给外部

(2)如果这个成员函数功能会在类外部被用到,并且需要被用户直接使用,则为public;如果这个函数只会在类内被使用,且易破坏对象状态,则为private

问题3:

接口1直接引用,性能高,使用const,数据无法被外部修改,安全性高

接口2需要额外复制,性能不高,使用const,安全性高

问题4:

程序可以正常运行,push_back先构造临时对象,再将其插入容器尾部,emplace_back直接在容器尾部的内存位置原地构造对象,无需临时对象,效率更高

 

实验任务2

源代码:

task2.cpp:

#include <iostream>
#include <vector>

void test1();
void test2();
void output1(const std::vector<int> &v);
void output2(const std::vector<int> &v);
void output3(const std::vector<std::vector<int>>& v);

int main() {
    std::cout << "深复制验证1: 标准库vector<int>\n";
    test1();

    std::cout << "\n深复制验证2: 标准库vector<int>嵌套使用\n";
    test2();
}

void test1() {
    std::vector<int> v1(5, 42);
    const std::vector<int> v2(v1);

    std::cout << "**********拷贝构造后**********\n";
    std::cout << "v1: "; output1(v1);
    std::cout << "v2: "; output1(v2);
    
    v1.at(0) = -1;

    std::cout << "**********修改v1[0]后**********\n";
    std::cout << "v1: "; output1(v1);
    std::cout << "v2: "; output1(v2); 
}

void test2() {
    std::vector<std::vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}};
    const std::vector<std::vector<int>> v2(v1);

    std::cout << "**********拷贝构造后**********\n";
    std::cout << "v1: "; output3(v1);
    std::cout << "v2: "; output3(v2);

    v1.at(0).push_back(-1);

    std::cout << "**********修改v1[0]后**********\n";
    std::cout << "v1: \n";  output3(v1);
    std::cout << "v2: \n";  output3(v2);
}

void output1(const std::vector<int> &v) {
    if(v.size() == 0) {
        std::cout << '\n';
        return;
    }
    
    std::cout << v.at(0);
    for(auto i = 1; i < v.size(); ++i)
        std::cout << ", " << v.at(i);
    std::cout << '\n';  
}

void output2(const std::vector<int> &v) {
    if(v.size() == 0) {
        std::cout << '\n';
        return;
    }
    
    auto it = v.begin();
    std::cout << *it;

    for(it = v.begin()+1; it != v.end(); ++it)
        std::cout << ", " << *it;
    std::cout << '\n';
}

void output3(const std::vector<std::vector<int>>& v) {
    if(v.size() == 0) {
        std::cout << '\n';
        return;
    }

    for(auto &i: v)
        output2(i);
}

 

运行结果截图:

任务2

问题1:

std::vector<int> v1(5, 42);构造v1,含有5个42,const std::vector<int> v2(v1);复制v1到v2,因此v2也有5个42

问题2:

v1.size()为2,v2.size()为2,v1[0].size()为3

问题3:

能实现同等效果,v1.at(0)=-1会检查边界,更安全,而v1[0]=-1不会,安全性较低

问题4:

(1)能输出-1,r为v1.at(0)的引用,r.at(r.size()-1)为r的最后一位,即为-1

(2)直接引用,效率更高,但不能修改

问题5:

(1)深复制,将v1修改后,v2没变

(2)当v是vector时v.at(0)返回值类型为int&,当v是const vector时,v.at(0)返回值类型为const int&,所以at()必须提供带const修饰的重载版本以满足const对象的需要

 

实验任务3

源代码:

vectorlnt.hpp:

#pragma once

#include <iostream>

class vectorInt{
public:
    vectorInt();
    vectorInt(int n_);
    vectorInt(int n_, int value);
    vectorInt(const vectorInt &vi);
    ~vectorInt();
    
    int size() const;
    int& at(int index);
    const int& at(int index) const;
    vectorInt& assign(const vectorInt &vi);

    int* begin();
    int* end();
    const int* begin() const;
    const int* end() const;

private:
    int n;
    int *ptr;
};

vectorInt::vectorInt():n{0}, ptr{nullptr} {
}

vectorInt::vectorInt(int n_): n{n_}, ptr{new int[n]} {
}

vectorInt::vectorInt(int n_, int value): n{n_}, ptr{new int[n_]} {
    for(auto i = 0; i < n; ++i)
        ptr[i] = value;
}

vectorInt::vectorInt(const vectorInt &vi): n{vi.n}, ptr{new int[n]} {
    for(auto i = 0; i < n; ++i)
        ptr[i] = vi.ptr[i];
}

vectorInt::~vectorInt() {
    delete [] ptr;
}

int vectorInt::size() const {
    return n;
}

const int& vectorInt::at(int index) const {
    if(index < 0 || index >= n) {
        std::cerr << "IndexError: index out of range\n";
        std::exit(1);
    }

    return ptr[index];
}

int& vectorInt::at(int index) {
    if(index < 0 || index >= n) {
        std::cerr << "IndexError: index out of range\n";
        std::exit(1);
    }

    return ptr[index];
}

vectorInt& vectorInt::assign(const vectorInt &vi) { 
    if(this == &vi) 
        return *this;

    int *ptr_tmp;
    ptr_tmp = new int[vi.n];
    for(int i = 0; i < vi.n; ++i)
        ptr_tmp[i] = vi.ptr[i];
    
    delete[] ptr;
    n = vi.n;
    ptr = ptr_tmp;
    return *this;
}

int* vectorInt::begin() {
    return ptr;
}

int* vectorInt::end() {
    return ptr+n;
}

const int* vectorInt::begin() const {
    return ptr;
}

const int* vectorInt::end() const {
    return ptr+n;
}

task3.cpp:

#include "vectorInt.hpp"
#include <iostream>

void test1();
void test2();
void output1(const vectorInt &vi);
void output2(const vectorInt &vi);

int main() {
    std::cout << "测试1: \n";
    test1();

    std::cout << "\n测试2: \n";
    test2();
}

void test1() {
    int n;
    std::cout << "Enter n: ";
    std::cin >> n;

    vectorInt x1(n);
    for(auto i = 0; i < n; ++i)
        x1.at(i) = (i+1)*10;
    std::cout << "x1: ";  output1(x1);

    vectorInt x2(n, 42);
    vectorInt x3(x2);
    x2.at(0) = -1;
    std::cout << "x2: ";  output1(x2);
    std::cout << "x3: ";  output1(x3);
}

void test2() {
    const vectorInt  x(5, 42);
    vectorInt y;

    y.assign(x);

    std::cout << "x: ";  output2(x);
    std::cout << "y: ";  output2(y);
}

void output1(const vectorInt &vi) {
    if(vi.size() == 0) {
        std::cout << '\n';
        return;
    }
        
    std::cout << vi.at(0);
    for(auto i = 1; i < vi.size(); ++i)
        std::cout << ", " << vi.at(i);
    std::cout << '\n';
}

void output2(const vectorInt &vi) {
    if(vi.size() == 0) {
        std::cout << '\n';
        return;
    }
    
    auto it = vi.begin();
    std::cout << *it;

    for(it = vi.begin()+1; it != vi.end(); ++it)
        std::cout << ", " << *it;
    std::cout << '\n';
}

运行结果截图:

任务3

问题1:

版本2先释放了内存,在分配新内存,此时vi就是assign指向的对象,vi.ptr指向的是已经释放的内存,存在问题

问题2:

(1)static_cast<const vectorInt*>(this)的作用是将this指针从vectorInt*类型转换为const vectorInt*类型,转换目的是转换后可以使用const类型

(2)const_caet<int&>的作用是将const int&类型转换为int&类型,转换目的是使其可以修改

问题3:

(1)非const类型调用v1,const类型调用v2

问题4:

可以,std::fill_n(ptr, n, value);功能是将ptr后的n个元素赋值为value;std::copy_n(vi.ptr, vi.n, ptr);功能是将vi.ptr后的vi.n个元素复制到ptr;std::copy_n(vi.ptr, vi.n, ptr_tmp);功能是将vi.ptr后的vi.n个元素复制到ptr_tmp

 

实验任务4

源代码:

matrix.hpp:

#pragma once

#include <iostream>
#include <algorithm>
#include <cstdlib>

class Matrix {
public:
    Matrix(int rows_, int cols_, double value = 0);
    Matrix(int rows_, double value = 0);
    Matrix(const Matrix &x);
    ~Matrix();

    void set(const double *pvalue, int size);
    void clear();
    
    const double& at(int i, int j) const;
    double& at(int i, int j);
    
    int rows() const;
    int cols() const;

    void print() const;

private:
    int n_rows;
    int n_cols;
    double *ptr;
};

matrix.cpp:

#include <iostream>
#include <cstdlib>
#include "matrix.hpp"

Matrix::Matrix(int rows_, int cols_, double value):n_rows(rows_),n_cols(cols_),ptr(new double[rows_*cols_]){
    for(int i=0;i<rows_*cols_;i++){
        ptr[i]=value;
    }
}

Matrix::Matrix(int rows_, double value):n_rows(rows_),n_cols(rows_),ptr(new double[rows_*rows_]){
    for(int i=0;i<rows_*rows_;i++){
        ptr[i]=value;
    }
}

Matrix::Matrix(const Matrix &x):n_rows(x.n_rows),n_cols(x.n_cols),ptr(new double[x.n_rows*x.n_cols]){
    for(int i=0;i<x.n_rows*x.n_cols;i++){
        ptr[i]=x.ptr[i];
    }
}

Matrix::~Matrix(){
    delete[] ptr;
}

void Matrix::set(const double *pvalue, int size){
    if(size!=n_rows*n_cols){
        std::cout<<"error";
        return;
    }
    else{
        for(int i=0;i<n_rows*n_cols;i++){
            ptr[i]=pvalue[i];
        } 
    }
}

void Matrix::clear(){
    for(int i=0;i<n_rows*n_cols;i++){
        ptr[i]=0;
    }
}

const double& Matrix::at(int i, int j) const{
    if(i<0||i>=n_rows||j<0||j>=n_cols){
        std::cout<<"error";
    }
    else{
        return ptr[i*n_cols+j];
    }
}

double& Matrix::at(int i, int j){
    if(i<0||i>=n_rows||j<0||j>=n_cols){
        std::cout<<"error";
    }
    else{
        return ptr[i*n_cols+j];
    }
}

int Matrix::rows() const{
    return n_rows;
}

int Matrix::cols() const{
    return n_cols;
}

void Matrix::print() const{
    for(int i=0;i<n_rows;i++){
        for(int j=0;j<n_cols;j++){
            std::cout<<at(i,j);
            if(j<n_cols-1){
                std::cout<<", ";
            }
        }
        std::cout<<"\n";
    }
}

task4.cpp:

#include <iostream>
#include <cstdlib>
#include "matrix.hpp"

void test1();
void test2();
void output(const Matrix &m, int row_index);

int main() {
    std::cout << "测试1: \n";
    test1();

    std::cout << "\n测试2: \n";
    test2();
}

void test1() {
    double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

    int n, m;
    std::cout << "Enter n and m: ";
    std::cin >> n >> m;

    Matrix m1(n, m);
    m1.set(x, n*m);

    Matrix m2(m, n);
    m2.set(x, m*n);

    Matrix m3(n);
    m3.set(x, n*n);

    std::cout << "矩阵对象m1: \n";   m1.print();
    std::cout << "矩阵对象m2: \n";   m2.print();
    std::cout << "矩阵对象m3: \n";   m3.print();
}

void test2() {
    Matrix m1(2, 3, -1);
    const Matrix m2(m1);
    
    std::cout << "矩阵对象m1: \n";   m1.print();
    std::cout << "矩阵对象m2: \n";   m2.print();

    m1.clear();
    m1.at(0, 0) = 1;

    std::cout << "m1更新后: \n";
    std::cout << "矩阵对象m1第0行 "; output(m1, 0);
    std::cout << "矩阵对象m2第0行: "; output(m2, 0);
}

void output(const Matrix &m, int row_index) {
    if(row_index < 0 || row_index >= m.rows()) {
        std::cerr << "IndexError: row index out of range\n";
        exit(1);
    }

    std::cout << m.at(row_index, 0);
    for(int j = 1; j < m.cols(); ++j)
        std::cout << ", " << m.at(row_index, j);
    std::cout << '\n';
}

运行结果截图:

任务4

 

实验任务5

源代码:

 contact.hpp:

#pragma once

#include <iostream>
#include <string>

class Contact {
public:
    Contact(const std::string &name_, const std::string &phone_);

    const std::string &get_name() const;
    const std::string &get_phone() const;
    void display() const;

private:
   std::string name;
   std::string phone;
};

Contact::Contact(const std::string &name_, const std::string &phone_):name{name_}, phone{phone_} {
}

const std::string& Contact::get_name() const {
    return name;
}

const std::string& Contact::get_phone() const {
    return phone;
}

void Contact::display() const {
    std::cout << name << ", " << phone;
}

contactBook.hpp:

# pragma  once

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include "contact.hpp"

class ContactBook {
public:
    void add(const std::string &name, const std::string &phone);
    void remove(const std::string &name);
    void find(const std::string &name) const;
    void display() const;
    size_t size() const;
    
private:
    int index(const std::string &name) const;
    void sort();

private:
    std::vector<Contact> contacts;
};

void ContactBook::add(const std::string &name, const std::string &phone) {
    if(index(name) == -1) {
        contacts.push_back(Contact(name, phone));
        std::cout << name << " add successfully.\n";
        sort();
        return;
    }

    std::cout << name << " already exists. fail to add!\n"; 
}

void ContactBook::remove(const std::string &name) {
    int i = index(name);

    if(i == -1) {
        std::cout << name << " not found, fail to remove!\n";
        return;
    }

    contacts.erase(contacts.begin()+i);
    std::cout << name << " remove successfully.\n";
}

void ContactBook::find(const std::string &name) const {
    int i = index(name);

    if(i == -1) {
        std::cout << name << " not found!\n";
        return;
    }

    contacts[i].display(); 
    std::cout << '\n';
}

void ContactBook::display() const {
    for(auto &c: contacts) {
        c.display(); 
        std::cout << '\n';
    }
}

size_t ContactBook::size() const {
    return contacts.size();
}

int ContactBook::index(const std::string &name) const{
    for(int i=0;i<contacts.size();i++){
        if(contacts[i].get_name()==name){
            return i;
        }
    } 
    return -1;
}

bool comparename(Contact &a,Contact &b){
    return a.get_name()<b.get_name();
}

void ContactBook::sort(){
    std::sort(contacts.begin(),contacts.end(),comparename);
}

task5.cpp:

#include "contactBook.hpp"

void test() {
    ContactBook contactbook;

    std::cout << "1. add contacts\n";
    contactbook.add("Bob", "18199357253");
    contactbook.add("Alice", "17300886371");
    contactbook.add("Linda", "18184538072");
    contactbook.add("Alice", "17300886371");

    std::cout << "\n2. display contacts\n";
    std::cout << "There are " << contactbook.size() << " contacts.\n";
    contactbook.display();

    std::cout << "\n3. find contacts\n";
    contactbook.find("Bob");
    contactbook.find("David");

    std::cout << "\n4. remove contact\n";
    contactbook.remove("Bob");
    contactbook.remove("David");
}

int main() {
    test();
}

运行结果截图:

任务5

 

posted @ 2025-11-23 19:08  系统警告  阅读(5)  评论(0)    收藏  举报