290. Word Pattern
Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Example 1: Input: pattern = "abba", str = "dog cat cat dog" Output: true Example 2: Input:pattern = "abba", str = "dog cat cat fish" Output: false Example 3: Input: pattern = "aaaa", str = "dog cat cat dog" Output: false Example 4: Input: pattern = "abba", str = "dog dog dog dog" Output: false Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space. // correct public class Solution { public boolean wordPattern(String pattern, String str) { String[] arr= str.split(" "); HashMap<Character, String> map = new HashMap<Character, String>(); if(arr.length!= pattern.length()) return false; for(int i=0; i<arr.length; i++){ char c = pattern.charAt(i); if(map.containsKey(c)){ if(!map.get(c).equals(arr[i])) return false; }else{ if(map.containsValue(arr[i])) return false; map.put(c, arr[i]); } } return true; } } // 31 / 33 test cases passed. Input: "abba" "dog dog dog dog" Output: true Expected: false class Solution { public boolean wordPattern(String pattern, String str) { HashMap<Character, String> map = new HashMap<>(); String[] array = str.split(" "); if(array.length != pattern.length()){ return false; }else{ for(int i = 0; i < pattern.length(); i++){ if(!map.containsKey(pattern.charAt(i))){ map.put(pattern.charAt(i), array[i]); }else{ if(!map.get(pattern.charAt(i)).equals(array[i])){ return false; } } } } return true; } }
posted on 2018-11-08 15:40 猪猪🐷 阅读(124) 评论(0) 收藏 举报
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