254. Factor Combinations
Numbers can be regarded as product of its factors. For example, 8 = 2 x 2 x 2; = 2 x 4. Write a function that takes an integer n and return all possible combinations of its factors. Note: 1. You may assume that n is always positive. 2. Factors should be greater than 1 and less than n. Example 1: Input: 1 Output: [] Example 2: Input: 37 Output:[] Example 3: Input: 12 Output: [ [2, 6], [2, 2, 3], [3, 4] ] Example 4: Input: 32 Output: [ [2, 16], [2, 2, 8], [2, 2, 2, 4], [2, 2, 2, 2, 2], [2, 4, 4], [4, 8] ] // other public List<List<Integer>> getFactors(int n) { List<List<Integer>> result = new ArrayList<List<Integer>>(); helper(result, new ArrayList<Integer>(), n, 2); return result; } public void helper(List<List<Integer>> result, List<Integer> item, int n, int start){ if (n <= 1) { if (item.size() > 1) { result.add(new ArrayList<Integer>(item)); } return; } for (int i = start; i <= n; ++i) { if (n % i == 0) { item.add(i); helper(result, item, n/i, i); item.remove(item.size()-1); } } }
public List<List<Integer>> getFactors(int n) { List<List<Integer>> res = new LinkedList<>(); backtrack(2, n, new LinkedList<>(), res); return res; } private void backtrack(int start, int n, List<Integer> list, List<List<Integer>> res){ for(int i = start; i * i <= n; i++) { if(n % i == 0) { list.add(i); list.add(n / i); res.add(new LinkedList<>(list)); list.remove(list.size() - 1); backtrack(i, n / i, list, res); list.remove(list.size() - 1); } } }
class Solution { public List<List<Integer>> getFactors(int n) { List<List<Integer>> res = new ArrayList<>(); dfs(res, new ArrayList<Integer>(), n, 2); return res; } private void dfs(List<List<Integer>> res, List<Integer> tmp, int n, int start){ // base case if(n <= 1){ if(n == 1 && tmp.size() > 1) res.add(new ArrayList<>(tmp)); return; } for(int i = start; i <= n; i++){ if(n % i == 0){ tmp.add(i); dfs(res, tmp, n / i, i); tmp.remove(tmp.size() - 1); } } } }
posted on 2018-11-06 09:27 猪猪🐷 阅读(101) 评论(0) 收藏 举报
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