123. Best Time to Buy and Sell Stock III
Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again). Example 1: Input: [3,3,5,0,0,3,1,4] Output: 6 Explanation: Buy on day 4 (price = 0) and sell on day 6 (price = 3), profit = 3-0 = 3. Then buy on day 7 (price = 1) and sell on day 8 (price = 4), profit = 4-1 = 3. Example 2: Input: [1,2,3,4,5] Output: 4 Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4. Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are engaging multiple transactions at the same time. You must sell before buying again. Example 3: Input: [7,6,4,3,1] Output: 0 Explanation: In this case, no transaction is done, i.e. max profit = 0. Time o(n^ 2) class Solution { public int maxProfit(int[] prices) { int res = 0; int left = 0; int right = 0; for(int i = 0; i < prices.length; i++){ left = stock1(prices, 0, i); right = stock1(prices, i + 1, prices.length - 1); res = Math.max(left + right, res); } return res; } private int stock1(int[] prices, int start, int end){ int res = 0; int min = Integer.MAX_VALUE; for(int i = start; i <= end; i++){ min = Math.min(min, prices[i]); res = Math.max(res, prices[i] - min); } return res; } } Solution Time o(n) ?
posted on 2018-11-06 07:43 猪猪🐷 阅读(91) 评论(0) 收藏 举报
浙公网安备 33010602011771号