343. Integer Break
343. Integer Break Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. Example 1: Input: 2 Output: 1 Explanation: 2 = 1 + 1, 1 × 1 = 1. Example 2: Input: 10 Output: 36 Explanation: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36. public int integerBreak(int n) { int[] dp = new int[n + 1]; dp[1] = 1; for(int i = 2; i <= n; i ++) { for(int j = 1; j < i; j ++) { dp[i] = Math.max(dp[i], (Math.max(j,dp[j])) * (Math.max(i - j, dp[i - j]))); } } return dp[n]; }
posted on 2018-09-20 18:11 猪猪🐷 阅读(68) 评论(0) 收藏 举报
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