343. Integer Break

343. Integer Break

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get.
Example 1:
Input: 2
Output: 1
Explanation: 2 = 1 + 1, 1 × 1 = 1.
Example 2:
Input: 10
Output: 36
Explanation: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36.


public int integerBreak(int n) {
       int[] dp = new int[n + 1];
       dp[1] = 1;
       for(int i = 2; i <= n; i ++) {
           for(int j = 1; j < i; j ++) {
               dp[i] = Math.max(dp[i], (Math.max(j,dp[j])) * (Math.max(i - j, dp[i - j])));
           }
       }
       return dp[n];
    }

 

posted on 2018-09-20 18:11  猪猪&#128055;  阅读(68)  评论(0)    收藏  举报

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