141. Linked List Cycle

/**
 * Definition for singly-linked list.
 * class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public boolean hasCycle(ListNode head) {
        if (head == null){
            return false;
        }

        // fast slow pointers 
        ListNode fast = head;
        ListNode slow = head;
        
        while(fast.next != null && fast.next.next != null){
            fast = fast.next.next;
            slow = slow.next;
            if(fast == slow){
                return true;
            }
        }
        return false;
    }
}

 

Given a linked list, determine if it has a cycle in it.

Follow up:
Can you solve it without using extra space?

 

posted on 2018-07-18 09:28  猪猪🐷  阅读(61)  评论(0)    收藏  举报

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