303. Range Sum Query - Immutable
public class NumArray { int[] nums; public NumArray(int[] nums) { this.nums = nums; for(int i = 1; i < nums.length; i++) nums[i] += nums[i - 1]; } public int sumRange(int i, int j) { if(i == 0) return nums[j]; return nums[j] - nums[i - 1]; } }
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.
Example:
Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3
posted on 2018-07-18 08:59 猪猪🐷 阅读(78) 评论(0) 收藏 举报
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