334. Increasing Triplet Subsequence
class Solution { public boolean increasingTriplet(int[] nums) { int m1 = Integer.MAX_VALUE; int m2 = Integer.MAX_VALUE; for(int num : nums){ if( m1 >= num){ m1 = num; }else if(m2 >= num){ m2 = num; }else{ return true; } } return false; } }
Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Note: Your algorithm should run in O(n) time complexity and O(1) space complexity.
Example 1:
Input: [1,2,3,4,5]
Output: true
Example 2:
Input: [5,4,3,2,1]
Output: false
posted on 2018-07-18 08:56 猪猪🐷 阅读(74) 评论(0) 收藏 举报
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