88. Merge Sorted Array

class Solution {
    public void merge(int[] nums1, int m, int[] nums2, int n) {
      int q = m + n -1;
      m = m - 1;
      n = n -1;
      while( m >= 0 && n >= 0){
        if(nums1[m] >= nums2[n]){
          nums1[q] = nums1[m];
          m--;
        }else{
          nums1[q] = nums2[n];
          n--;
        }
        q--;
      }
      
      while( n >= 0){
        nums1[q] = nums2[n];
        q--;
        n--;
      }
    }
}

 

88. Merge Sorted Array


// https://leetcode.com/problems/merge-sorted-array/


Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. 
The number of elements initialized in nums1 and nums2 are m and n respectively.

public void merge(int[] nums1, int m, int[] nums2, int n) {
    int k = m + n - 1, i = m - 1, j = n - 1;
    while (i >= 0 && j >= 0) {
        if (nums1[i] >= nums2[j])    nums1[k--] = nums1[i--];
        else    nums1[k--] = nums2[j--];
    }
    while (j >= 0)   nums1[k--] = nums2[j--];
}

 

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:

  • The number of elements initialized in nums1 and nums2 are m and n respectively.
  • You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.

Example:

Input:
nums1 = [1,2,3,0,0,0], m = 3
nums2 = [2,5,6],       n = 3

Output: [1,2,2,3,5,6]

posted on 2018-07-18 08:49  猪猪🐷  阅读(105)  评论(0)    收藏  举报

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