88. Merge Sorted Array
class Solution { public void merge(int[] nums1, int m, int[] nums2, int n) { int q = m + n -1; m = m - 1; n = n -1; while( m >= 0 && n >= 0){ if(nums1[m] >= nums2[n]){ nums1[q] = nums1[m]; m--; }else{ nums1[q] = nums2[n]; n--; } q--; } while( n >= 0){ nums1[q] = nums2[n]; q--; n--; } } }
88. Merge Sorted Array // https://leetcode.com/problems/merge-sorted-array/ Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively. public void merge(int[] nums1, int m, int[] nums2, int n) { int k = m + n - 1, i = m - 1, j = n - 1; while (i >= 0 && j >= 0) { if (nums1[i] >= nums2[j]) nums1[k--] = nums1[i--]; else nums1[k--] = nums2[j--]; } while (j >= 0) nums1[k--] = nums2[j--]; }
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 Output: [1,2,2,3,5,6]
posted on 2018-07-18 08:49 猪猪🐷 阅读(105) 评论(0) 收藏 举报
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