12 2020 档案

LeetCode38-countAndSay
摘要：递归： if( n == 1) return "1"; String s = countAndSay(n-1); char[] c = s.toCharArray(); int count = 1; String res = ""; for(int i = 0; i < c.length-1; i+ 阅读全文
posted @ 2020-12-03 11:04 Amazon_Tina 阅读(65) 评论(0) 推荐(0)