摘要:
更好的遍历Josn的方法,利用jquery的each方法: var arr1 = [ "one", "two", "three", "four", "five" ]; $.each(arr1, function(){ alert(this); }); 输出:one two three four five var arr2 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] $.each(arr2, function(i, item){ alert(item[0]); }); 阅读全文
posted @ 2013-06-23 13:11
李天翔
阅读(260)
评论(0)
推荐(0)


浙公网安备 33010602011771号