2019年10月20日
摘要: 1 #include<iostream> 2 #include<string> 3 #include<queue> 4 #include<stack> 5 #include<vector> 6 #include<map> 7 #include<cstdio> 8 #include<cstdlib> 阅读全文
posted @ 2019-10-20 21:06 thjkhdf12 阅读(91) 评论(0) 推荐(0)
摘要: 1 #include<iostream> 2 #include<stack> 3 #include<vector> 4 #include<algorithm> 5 using namespace std; 6 7 const int maxn = 10010; 8 int n, m; 9 int d 阅读全文
posted @ 2019-10-20 21:05 thjkhdf12 阅读(93) 评论(0) 推荐(0)
摘要: 1 #include<iostream> 2 #include<stack> 3 #include<vector> 4 #include<set> 5 #include<algorithm> 6 using namespace std; 7 8 const int maxn = 10010; 9 i 阅读全文
posted @ 2019-10-20 21:04 thjkhdf12 阅读(98) 评论(0) 推荐(0)
摘要: 1 #include<iostream> 2 #include<string> 3 #include<queue> 4 #include<stack> 5 #include<vector> 6 #include<map> 7 #include<cstdio> 8 #include<cstdlib> 阅读全文
posted @ 2019-10-20 21:04 thjkhdf12 阅读(109) 评论(0) 推荐(0)
摘要: 1 #include<iostream> 2 #include<string> 3 #include<queue> 4 #include<stack> 5 #include<vector> 6 #include<map> 7 #include<cstdio> 8 #include<cstdlib> 阅读全文
posted @ 2019-10-20 21:03 thjkhdf12 阅读(105) 评论(0) 推荐(0)
摘要: int dfn[maxn]; //第i个点被dfs到次序 int low[maxn]; //二叉搜索树上i所在子数上仍在栈中的最小dfn,low[i]相等的点在一个强连通分量中 bool vis_tarjan[maxn]; stack<int>s_tarjan; int tot_tarjan; in 阅读全文
posted @ 2019-10-20 16:57 thjkhdf12 阅读(153) 评论(0) 推荐(0)