摘要: 便捷方法 struct Node { int x,y; bool operator <(Node a) const { return y < a.y; } bool operator >(Node a) const { return y > a.y; } }; priority_queue<Node 阅读全文
posted @ 2020-11-23 20:09 tao10203 阅读(645) 评论(0) 推荐(0)