摘要: ## 找出所有后代数据 with getTree as ( select parent_id, id from a where a.id = #{id}; UNION all select a.parent_id, a.id from a inner join getTree on a.parent 阅读全文
posted @ 2021-08-09 19:05 随笔~~~~~~ 阅读(586) 评论(0) 推荐(0)