摘要: ``` class Solution { public: ListNode* reverse(ListNode* head)//翻转以head为头节点的链表 { if(!head||!head->next) return head; auto a=head,b=head->next; while(b 阅读全文
posted @ 2023-07-12 12:17 穿过雾的阴霾 阅读(7) 评论(0) 推荐(0)