摘要: ``` class Solution { public: vector dfs(int l,int r)//返回以n为根节点的所有可能子树 { vector res; if(l>r) return {NULL}; for(int k=l;k left=dfs(l,k-1); vector right 阅读全文
posted @ 2023-05-23 10:50 穿过雾的阴霾 阅读(11) 评论(0) 推荐(0)