摘要: 检查list包含list的情况 List<string> a = ... List<string> b = ... var inComon = a.Intersect(b).Any(); Use Enumerable.Any Method: List<string> l1 = new List<st 阅读全文
posted @ 2021-10-22 18:21 【唐】三三 阅读(431) 评论(0) 推荐(0)