最小公倍数
摘要:
#include<stdio.h>long long n;long long gcd( long long n,long long m ){ return m ? gcd( m,n % m ):n;}long long cal( ){ long long sum = 1,c; for( long long i = 1; i <= n; ++i ) scanf( "%I64d",&c ),sum =... 阅读全文
posted @ 2011-04-29 13:57 more think, more gains 阅读(167) 评论(0) 推荐(0)