Sicily 1152 & 1153 简单的马周游问题

这题做得相当曲折，一开始以为是和8皇后差不多，于是按8皇后解法做，后来发现自己列出所有的路线，错了

修改后，发现超时了，后来改了好几次都超时了， 看了大牛的解题报告，才知道要剪枝

先搜索扩展点最小的点， 因为它的扩展点小，就意味着从其它点到达它的路径很少，先搜索它会提高效率

这是我个人的理解

1152和1153都差不多，只不过1153数据规模比1152数据规模大

1152

#include <iostream>
#include <vector>
#include <memory.h>
#include <algorithm>


using namespace std;

struct point
{
	int x;
	int y;
	int totaltonext;

};

int board[10][10];

int move_x[] = {-1, -1, -2, -2, 1, 1, 2, 2};
int move_y[] = {-2, 2, 1, -1, 2, -2, 1, -1};

int path[30];
bool dfs(point, int);
bool isvalue(point );
bool cmp(point , point );

int main()
{
	int n;
	point p;


	//freopen("C:\\Users\\Haojian\\Desktop\\test.txt", "r", stdin);
	while (cin >> n && n != -1)
	{
		isfind = false;
		memset(board, 0, 10*10*sizeof(int));
		p.x = (n - 1) / 6 + 1;
		p.y = n - ((p.x-1) * 6);
		//p.num = 1;
		//	path[p.num-1] = n;
		path[0] = n;
		board[p.x][p.y] = 1;
		dfs (p, 1);

	}
	return 0;
}


bool dfs (point p, int current)
{
	point n;


	if (current == 30)
	{
		for (int i = 0; i < 29; i++)
			cout << path[i] << " ";
		cout << path[29];
		cout << endl;
		return true;
	}
	else
	{
		vector<point> tmp;
		for (int i = 0; i < 8; i++)
		{
			n.x = p.x + move_x[i];
			n.y = p.y + move_y[i];
			n.totaltonext = 0;

			if (isvalue(n))
			{

				point k;
				for (int j = 0; j < 8; j++)
				{
					k.x = n.x + move_x[j];
					k.y = n.y + move_y[j];
					if (isvalue(k))
						n.totaltonext++;
				}
				tmp.push_back(n);
			}
		}//计算下一个要找的点的扩展点

		sort(tmp.begin(), tmp.end(), cmp);//按扩展点从小到大排序

		//从扩展点小的开始搜索
		for (int i = 0; i < tmp.size(); i++)
		{
			board[tmp[i].x][tmp[i].y] = 1;
			path[current] = (tmp[i].x - 1) * 6 + tmp[i].y;
			if (dfs(tmp[i], current+1)) return true;
			board[tmp[i].x][tmp[i].y] = 0;
		}



	}
	return false;
}

bool cmp(point a, point b)
{
	return a.totaltonext < b.totaltonext;
}

bool isvalue(point n)
{
	return (n.x >= 1 && n.x <= 5 && n.y >= 1 && n.y <= 6 && !board[n.x][n.y]);
}

1153

#include <iostream>
#include <vector>
#include <memory.h>
#include <algorithm>


using namespace std;

struct point
{
	int x;
	int y;
	int totaltonext;

};

int board[10][10];

int move_x[] = {-1, -1, -2, -2, 1, 1, 2, 2};
int move_y[] = {-2, 2, 1, -1, 2, -2, 1, -1};

bool isfind;
int path[100];
bool dfs(point, int);
bool isvalue(point );
bool cmp(point , point );

int main()
{
	int n;
	point p;
	

	//freopen("C:\\Users\\Haojian\\Desktop\\test.txt", "r", stdin);
	while (cin >> n && n != -1)
	{
		isfind = false;
		memset(board, 0, 10*10*sizeof(int));
		p.x = (n - 1) / 8 + 1;
		p.y = n - ((p.x-1) * 8);
		//p.num = 1;
	//	path[p.num-1] = n;
		path[0] = n;
		board[p.x][p.y] = 1;
		dfs (p, 1);

	}
	return 0;
}


bool dfs (point p, int current)
{
	point n;

	
	if (current == 64)
	{
		for (int i = 0; i < 63; i++)
			cout << path[i] << " ";
		cout << path[63];
		cout << endl;
		return true;
	}
	else
	{
		vector<point> tmp;
		for (int i = 0; i < 8; i++)
		{
			n.x = p.x + move_x[i];
			n.y = p.y + move_y[i];
			n.totaltonext = 0;
			
			if (isvalue(n))
			{
				
				point k;
				for (int j = 0; j < 8; j++)
				{
					k.x = n.x + move_x[j];
					k.y = n.y + move_y[j];
					if (isvalue(k))
						n.totaltonext++;
				}
				
					tmp.push_back(n);
			}
		}

		sort(tmp.begin(), tmp.end(), cmp);
		
		for (int i = 0; i < tmp.size(); i++)
		{
			board[tmp[i].x][tmp[i].y] = 1;
			path[current] = (tmp[i].x - 1) * 8 + tmp[i].y;
			if (dfs(tmp[i], current+1)) return true;
			board[tmp[i].x][tmp[i].y] = 0;
		}
		

		
	}
	return false;
}

bool cmp(point a, point b)
{
	return a.totaltonext < b.totaltonext;
}

bool isvalue(point n)
{
	return (n.x >= 1 && n.x <= 8 && n.y >= 1 && n.y <= 8 && !board[n.x][n.y]);
}