摘要: Given amxnmatrix, if an element is 0, set its entire row and column to 0. Do it in place.Follow up:Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple improvement uses O(m+n) space, but still not the best solution.Could you devise a constant space so 阅读全文
posted @ 2013-08-20 20:42 懒猫欣 阅读(155) 评论(0) 推荐(0)
摘要: Given a linked list, remove thenthnode from the end of list and return its head.For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5.Note:Givennwill always be valid.Try to do this in one pass./* 阅读全文
posted @ 2013-08-20 01:43 懒猫欣 阅读(164) 评论(0) 推荐(0)
摘要: Given an array and a value, remove all instances of that value in place and return the new length.The order of elements can be changed. It doesn't matter what you leave beyond the new length.class Solution {public: int removeElement(int A[], int n, int elem) { int ptr=n-1; int lengt... 阅读全文
posted @ 2013-08-20 01:23 懒猫欣 阅读(181) 评论(0) 推荐(0)
摘要: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving onlydistinctnumbers from the original list.For example,Given1->2->3->3->4->4->5, return1->2->5.Given1->1->1->2->3, return2->3./** * Definition for singly-linked list. * struct Lis 阅读全文
posted @ 2013-08-20 01:03 懒猫欣 阅读(132) 评论(0) 推荐(0)
摘要: Given a sorted linked list, delete all duplicates such that each element appear onlyonce.For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3./** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val 阅读全文
posted @ 2013-08-20 00:52 懒猫欣 阅读(145) 评论(0) 推荐(0)