MOOC清华《面向对象程序设计》第4章:强制类型转换实验
#include <iostream>
using namespace std;
class B{
public:
virtual void f() {}
};
class D : public B{};
class E{};
int main(){
D d1;
B b1;
//d1 = static_cast<D>(b1);//ERROR:从基类无法转换回派生类
b1 = static_cast<B>(d1);//OK!可以从派生类转换成基类
//b1 = dynamic_cast<B>(d1);//ERROR:被转换的必须是引用或指针
B* pB1 = new B();
D* pD1 = static_cast<D*>(pB1);
if(pD1) cout << "static_cast, B* --> D* : OK" << endl;
if(!pD1) cout << "static_cast, B* --> D* : Failed" << endl;
pD1 = dynamic_cast<D*>(pB1);
if(pD1) cout << "dynamic_cast, B* --> D* : OK" << endl;
if(!pD1) cout << "dynamic_cast, B* --> D* : Failed" << endl;
D* pD2 = new D();
B* pB2 = static_cast<B*>(pD2);
if(pB2) cout << "static_cast, D* --> B* : OK" << endl;
if(!pB2) cout << "static_cast, D* --> B* : Failed" << endl;
pB2 = dynamic_cast<B*>(pD2);
if(pB2) cout << "dynamic_cast, D* --> B* : OK" << endl;
if(!pB2) cout << "dynamic_cast, D* --> B* : Failed" << endl;
E* pE = dynamic_cast<E*>(pB1);
if(pE) cout << "dynamic_cast, B* --> E* : OK" << endl;
if(!pE) cout << "dynamic_cast, B* --> E* : Failed" << endl;
//pE = static_cast<E*>(pB1);//ERROR:没有继承关系不能转换
//E e = static_cast<E>(pB1);//ERROR:没有提供转换途径
return 0;
}
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posted on 2017-10-05 18:17 sunshineman1986 阅读(113) 评论(0) 收藏 举报
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