摘要: -- oracle分组排序取出每组顺序第一条 select * from ( select row_number() over(partition by user_code order by create_time desc) rn, t.* from your_table t ) where rn 阅读全文
posted @ 2024-12-17 14:14 一隅桥畔 阅读(520) 评论(0) 推荐(0)