摘要: -- 查询倒数第二条 select * from (select row_number() over(order by pay_no desc) rn, t.* from tm_pm_pay t where hospital_code = '0002') where rn = 2 阅读全文
posted @ 2022-09-28 10:02 一隅桥畔 阅读(800) 评论(0) 推荐(0)