A+B for Polynomials
Q:This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10,0 <= NK < ... < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input
2 1 2.4 0 3.2 2 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2
A: two pointers问题,注意一个细节就好:当两个系数相加时,可能和为0,此时,非零项计数不能把这项包括在内。
#include <stdio.h>
int main()
{
int K1,K2,K,exps1[10],exps2[10],exp[20];
int i,j;
float coes1[10],coes2[10],coe[20];
scanf("%d ",&K1);
for(i=0;i<K1;i++)
{
scanf("%d",&exps1[i]);
scanf("%f",&coes1[i]);
}
scanf("%d ",&K2);
for(i=0;i<K2;i++)
{
scanf("%d",&exps2[i]);
scanf("%f",&coes2[i]);
}
i=j=K=0;
while (i<K1&&j<K2)
{
if(exps1[i]==exps2[j])
{
exp[K] = exps1[i];
coe[K] = coes1[i]+coes2[j];
if(coe[K]!=0) //注意相加之后,可能这一项的系数为0
K++;
i++;
j++;
}else if(exps1[i]>exps2[j])
{
exp[K] = exps1[i];
coe[K] = coes1[i];
K++;
i++;
}else
{
exp[K] = exps2[j];
coe[K] = coes2[j];
K++;
j++;
}
}
while(i<K1)
{
exp[K] = exps1[i];
coe[K] = coes1[i];
K++;
i++;
}
while(j<K2)
{
exp[K] = exps2[j];
coe[K] = coes2[j];
K++;
j++;
}
printf("%d",K);
for (i=0;i<K;i++)
printf(" %d %.1f",exp[i],coe[i]);
printf("\n");
return 0;
}
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