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方法一,使用model_to_dict from django.forms.models import model_to_dict list = ProjectCase.objects.filter(prj_id=prj_id).order_by('-prc_id') data = [] 阅读全文
posted @ 2022-10-19 12:02
sugoi
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摘要:
实现代码如下 from django.core.paginator import Paginator, PageNotAnInteger, EmptyPage from django.forms.models import model_to_dict def getProjectResultLi 阅读全文
posted @ 2022-10-19 11:48
sugoi
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