摘要:
在 insert 数据时报错: SELECT t.name AS TableName, c.name AS ColumnName, ic.is_identity AS IsIdentityColumn FROM sys.tables t JOIN sys.columns c ON t.object_ 阅读全文
摘要:
<?php header("Content-type: text/html; charset=utf-8"); $p13=$str['UserId']; //获取当前访问者唯一id:P13 $sql_num="select count(*)as num from yb_grade where p13 阅读全文