摘要: 1.浏览器发送POST请求 方法一: var xml = new XMLHttpRequest(); var url = "http://127.0.0.1:8800/admin/user"; xml.open("POST", url, true); xml.setRequestHeader("Co 阅读全文
posted @ 2022-10-21 10:47 sowler 阅读(524) 评论(0) 推荐(0)