HDU 1003 Max Sum

//简单DP,状态转移方程:dp[i] = max( a[i], a[i]+dp[i-1] )
#include <iostream>
#include <cstring>
#include <cmath>
using namespace std;

int a[100005];
int main()
{
    int t, n, cnt=0;
    cin >> t;
    while (t--)
    {
        cin >> n;
        int i;
        for (i=0; i<n; i++)
            cin >> a[i];
        //start = max(a[i], a[i]+start);
        //maxsum = (maxsum, start);
        int start=a[0], maxsum=a[0], begin=0, end=0, pos=0;
        for (i=1; i<n; ++i)
        {
            if (start+a[i]<a[i]){
                start = a[i];
                pos = i;    //变化的位置
            }
            else
                start += a[i];
            if (start > maxsum)
            {
                maxsum = start;
                end = i;
                begin = pos;    //当end变化时,begin才能变化
            }
        }
        cout << "Case " << ++cnt << ":" << endl;
        cout << maxsum << " " << begin+1 << " " << end+1 << endl;
        //最后貌似没有换行了,刚刚做其他的题PE了,这回写上直接A了,不知道直接换2行对不对。。。
        if (t != 0)
            cout << endl;
    }
    return 0;
}

 

posted on 2013-06-17 19:40  soul214j  阅读(99)  评论(0)    收藏  举报