寻找大富翁

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4574    Accepted Submission(s): 1857


Problem Description
浙江桐乡乌镇共有n个人,请找出该镇上的前m个大富翁.
 

 

Input
输入包含多组测试用例.
每个用例首先包含2个整数n(0<n<=100000)和m(0<m<=10),其中: n为镇上的人数,m为需要找出的大富翁数, 接下来一行输入镇上n个人的财富值.
n和m同时为0时表示输入结束.
 

 

Output
请输出乌镇前m个大富翁的财产数,财产多的排前面,如果大富翁不足m个,则全部输出,每组输出占一行.
 

 

Sample Input
3 1
2 5 -1
5 3
1 2 3 4 5
0 0
 

 

Sample Output
5
5 4 3
 

 

Source
 

 

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 1 #include <queue>
 2 #include <cstdio>
 3 #include <iostream>
 4 using namespace std;
 5 int main()
 6 {
 7     int n, m, i, p;
 8     
 9     while(~scanf("%d %d", &n, &m), m+n)
10     {
11         
12         priority_queue<int, vector<int>, less<int> >q;
13         for(i=0; i<n; i++)
14         {
15             scanf("%d", &p);
16             q.push(p);
17         }
18         printf("%d",q.top());
19         q.pop();
20         int total = 1;
21         while(!q.empty())
22         {
23             if(total == m)
24             break;
25             printf(" %d",q.top());
26             q.pop();
27             total++;
28         }
29         printf("\n");
30         
31     }
32     return 0;
33 }

 

 

 
 
posted on 2015-07-28 20:54  cleverbiger  阅读(219)  评论(0编辑  收藏  举报